y^2+2yz-120z^2=

Solution for y^2+2yz-120z^2= equation:

Simplifying
y2 + 2yz + -120z2 = 0

Reorder the terms:
2yz + y2 + -120z2 = 0

Solving
2yz + y2 + -120z2 = 0

Solving for variable 'y'.

Factor a trinomial.
(y + -10z)(y + 12z) = 0

Subproblem 1
Set the factor '(y + -10z)' equal to zero and attempt to solve:

Simplifying
y + -10z = 0

Solving
y + -10z = 0

Move all terms containing y to the left, all other terms to the right.

Add '10z' to each side of the equation.
y + -10z + 10z = 0 + 10z

Combine like terms: -10z + 10z = 0
y + 0 = 0 + 10z
y = 0 + 10z
Remove the zero:
y = 10z

Simplifying
y = 10z
Subproblem 2
Set the factor '(y + 12z)' equal to zero and attempt to solve:

Simplifying
y + 12z = 0

Solving
y + 12z = 0

Move all terms containing y to the left, all other terms to the right.

Add '-12z' to each side of the equation.
y + 12z + -12z = 0 + -12z

Combine like terms: 12z + -12z = 0
y + 0 = 0 + -12z
y = 0 + -12z
Remove the zero:
y = -12z

Simplifying
y = -12z
Solution
y = {10z, -12z}